Margot Robbie, the stunning Australian actress, turned heads at the premiere of “Whiskey Tango Foxtrot” with her choice of attire. She wore a plunging black dress that accentuated her curves and showcased her ample cleavage. The dress was designed by Proenza Schouler and featured a fitted bodice that flared out into a flowing skirt.
Robbie was joined at the premiere by other celebrities, including her co-star Tina Fey and the film’s director Glenn Ficarra. The event was held at the AMC Loews Lincoln Square theater in New York City and was attended by a host of other A-listers.
Robbie’s daring fashion choice received a lot of attention from the press and fans alike. Many praised her for her confidence and her ability to pull off such a bold look with ease. Her appearance at the premiere once again cemented her status as one of Hollywood’s most fashionable and stylish stars.
“Whiskey Tango Foxtrot” is a comedy-drama film that follows the story of a journalist who travels to Afghanistan to cover the war. The film was well-received by critics and audiences and helped to further establish Robbie as a talented actress with a bright future in Hollywood.
Overall, Robbie’s appearance at the “Whiskey Tango Foxtrot” premiere was a memorable one, thanks in no small part to her stunning black dress. Her confidence and poise on the red carpet have once again shown why she is considered one of the most exciting and talented actresses in the entertainment industry today.
Margot Robbien stunned on the red carpet at the New York premiere of Whiskey Tango Foxtrot on Tuesday night.
Source: https://www.dailymail.co.uk
